22x^2-85x+28=(

Solution for 22x^2-85x+28=( equation:

22x^2-85x+28=(

We move all terms to the left:

22x^2-85x+28-(()=0

We add all the numbers together, and all the variables

22x^2-85x=0

a = 22; b = -85; c = 0;
Δ = b2-4ac
Δ = -852-4·22·0
Δ = 7225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7225}=85$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-85}{2*22}=\frac{0}{44}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+85}{2*22}=\frac{170}{44}
=3+19/22
$